(x+10)(x-5)=x^2+1

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Solution for (x+10)(x-5)=x^2+1 equation:


Simplifying
(x + 10)(x + -5) = x2 + 1

Reorder the terms:
(10 + x)(x + -5) = x2 + 1

Reorder the terms:
(10 + x)(-5 + x) = x2 + 1

Multiply (10 + x) * (-5 + x)
(10(-5 + x) + x(-5 + x)) = x2 + 1
((-5 * 10 + x * 10) + x(-5 + x)) = x2 + 1
((-50 + 10x) + x(-5 + x)) = x2 + 1
(-50 + 10x + (-5 * x + x * x)) = x2 + 1
(-50 + 10x + (-5x + x2)) = x2 + 1

Combine like terms: 10x + -5x = 5x
(-50 + 5x + x2) = x2 + 1

Reorder the terms:
-50 + 5x + x2 = 1 + x2

Add '-1x2' to each side of the equation.
-50 + 5x + x2 + -1x2 = 1 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-50 + 5x + 0 = 1 + x2 + -1x2
-50 + 5x = 1 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-50 + 5x = 1 + 0
-50 + 5x = 1

Solving
-50 + 5x = 1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '50' to each side of the equation.
-50 + 50 + 5x = 1 + 50

Combine like terms: -50 + 50 = 0
0 + 5x = 1 + 50
5x = 1 + 50

Combine like terms: 1 + 50 = 51
5x = 51

Divide each side by '5'.
x = 10.2

Simplifying
x = 10.2

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